# Hot Air Balloon Project

### By Ricky Guevara & Anthony Carroll

## Question One

## Question Two

P.S. If your wondering I put -5 in the graph to represent 5 minuets before the balloon was sighted.

## Refer to the graph on the google doc for all questions

## Question Three

## Question Four

## Question Five

The function to represent the situation is f(x)= 1200 - 20x

Five B:

So the first balloon will land 20 minuets before the second. The separation is 40 min. to 60 min.

Five C:

Since balloon two was spotted higher at 1200 and has the same decent rate as balloon one witch was spotted lower at 800, then of course the second balloon would end.

## Question Six

The Function the represents balloon threes situation is f(x)=800 - 30x

Six B:

The third balloon is going to end 13 minuets earlier then the first because it is decreasing 10 feet faster a minuet.

Six C:

Both balloon One and three have the same staring point but since the third balloon is descending at a fasters rate of 30 ft. per minuet it lands faster.

## Question Seven

The function that works for this is f(x)=0 + 30x

Seven B:

The First and fourth balloon will be at the same hight 480 feet off the ground, and in 16 minuets.

Seven C:

Graphically this means that at that point the balloons are tied and not different in any way.

## Question Eight

It would have to begin it decent at 1200 feet.

Eight B:

The function that fits this situation is f(x)=1200 - 30x