Trapezoid
unit 6 project by Kenia Garcia
Figure F coordinates
B ( 3, 3 )
C ( 8, -1 )
D ( -7,-1 )
Slopes of the trapezoid/proving that it's a trapezoidSlopes: AB = 0/1 BC = -4/5 CD = 0/1 AD= 1/5 Does the figure have a set of parallel lines? -Yes,only one.Lines AB and CD both have the same slope,therefore that means that AB and CD are parallel which proves that it is a trapezoid. (work is shown in the photo) | Is it perpendicular? No,although BC and AD have different slopes,they're both fractions. | Side Lengths AB = 5 BC = 6.4 CD = 15 AD = 6.4 (work shown in photo) |
Slopes of the trapezoid/proving that it's a trapezoid
Slopes:
AB = 0/1
BC = -4/5
CD = 0/1
AD= 1/5
Does the figure have a set of parallel lines?
-Yes,only one.Lines AB and CD both have the same slope,therefore that means that AB and CD are parallel which proves that it is a trapezoid.
(work is shown in the photo)
Area Since the figure is a trapezoid,I used the trapezoid area formula. A = 1/2(b1 + b2) h A = 1/2(5 + 15)4 A=1/2(20)4 A=1/2(80) A=40 units | Equations for original lines | Midpoints |
Connecting midpoints and creating the new shape After I found my midpoints,I connected them and created a parallelogram. | PerimeterIn order to find the perimeter,I had to find the distance to one midpoint to another. (work shown in picture) *The square root of 29 was 5.3 , the work was cut offed by the picture sizing restrictions. | Perimeter (cont.) Then after I found the length/distance,I added the distances all together to get 20.78 (rounded) or 20.8 . 5.3 + 5.3 + 5.09 + 5.09 = 20.78 |
Connecting midpoints and creating the new shape
Perimeter
In order to find the perimeter,I had to find the distance to one midpoint to another.
(work shown in picture)
*The square root of 29 was 5.3 , the work was cut offed by the picture sizing restrictions.