Sodium and Water
By Lauren Anderson 1st
What is a Stoichiometry?
Na + H20
So lets get Started!
First take your reaction and find out what type it is. My reaction above is a single replacement because it has one element and one compound. After you do that set up and balanced your equation and make sure to include the states of matter.
Example: 2Na + 2HOH - 2NaOH (S) + H2 (aq)
Then, you will calculate the mole to mole conversions where you will take mole "A" and multiply by mole "B" and then divide by Mole "A" . After that you will find the mass to mass conversion just follow the steps in the giant picture below. After you done that you will find your limiting reactant which is your reactant with the lease number of that element or compound. You will do the same conversions but just a total of two. When you find your smallest number that will be your Theoretical yield. Finally you will find your percent yield by dividing the actual yield by the theoretical yield the multiplying it by 100.
Need to Know
Make sure you know the basics of your reaction like the names.
Na- sodium , H20-Water , H-Hydrogen , and NaOH- Sodium hydroxide. And after you identify the names of your elements and compounds find their molar mass. The molar mass is the mass of your element or compound located on the periodic table. If you have to elements together, Just add up both of their molar masses together. And don't forget to include the subscripts and not the coefficients.
Example: Na-22.990 , H2O-18.015 , H2-2.016 , NaOH-39.997 , HOH-18.015
My Equation Example
- Na + H20 ( Single Replacement)
- 2Na + 2HOH - 2NaOH(S) + H2(aq) Balanced
- 1.06 Na times 1H2 divided by 2Na (Mole to mole)
- Mass to Mass
- Limiting reactant
- Theoretical yield 21.04 of NaOH
- Percent yield