Chapter 10

Joe V

Formulas

Area of a parallelogram= b*h

area of a trapazoid=1/2(b1+b2)*h

area of a circle=3.14r*r

surface area of a prism=2b+Ph

surface area of a cylinder=2B+Ch=2*3.14r*r+2*3.14rh

surface area of a pyramid=B+1/2pl

surface area of a cone=3.14r*r+3.14r*l

volume of a prism=Bh

volume of a cylinder=3.14r*r*h

volume of a pyramid=1/3Bh

volume of a cone=1/3*3.14r*r*h

Section 1

practice problem

A parallelogram is 5 ft wide and 3 feet tall. what is the area of the parallelogram?

A=bh

A=5*3

answer is 15ft squared

Another practice problem

a trapezoid has the with of 4in for one base and 8in for the second base and a height of 3. what is the area of the trapezoid?

A=1/2(b1+b2)h

A=1/2(4+8)3

A=18in squared

Area of a Trapezoid

Section 2

Area of a circle

Big image

Practice problem

A circle has the radius of 6cm. what is the area of the circle?

A=3.14r*r

A=3.14*6*6

A=36*pi cm squared

Section 3

Classifying objects

Section 4

Surface areas of prisms and cylinders

Practice problem

you are making a toy chest that is 5 feet wide 9 feet in length and is 2 feet tall. what is the surface area of the toy chest?

S=2B+Ph

S=2(5*9)+(5+9+5+9)2

S=90+56

S=146ft

Section 5

Surface areas of pyramids and cones

Practice problem

S=B+1/2Pl

S=2*8+1/2(2+2+8+8)6

S=16+60

S=76in

Section 6

Volume of prisms and cylinders

practice problem

a rectangular prism has the width of 8in, the length of 12in and the height of 2. whats the volume of the prism?

V=Bh

V=12*8*2

V=192

Cylinder Volume and Surface Area