Solveing Stoichiometry
Sean Everhart
Reaction
Type of Reaction
Balanced Equation
Reactants
Silver Nitrate
3. This compound is a versatile precursor to many other silver compounds, such as those used in photograthy.
Plus
Lead
Products
Plus
Lead Nitrate
IUPAC Naming
Molar Mass of Reactants and Product
Using that find the mass of each.
Ex.
207.2+(169.872)--->269.204+107.868
Pb + Ag(NO3)-------> Pb(NO3) + Ag
Mole to Mole Conversions
When i did this conversion through the table my "Mole A" (given from question) was 2.11 moles of Pb. My "Mole B" (Ag(NO3)) had the Coefficient of 2. And my second "Mole A" had a Coefficient of 1. Multiplying by the top then Dividing by the bottom i got
4.22 moles of (Ag(NO3)).
Video Example of Mole to Mole and Mass to Mass
Mass to Mass Conversions
In my Reaction
12.1g Pb- Grams A
207.2g Pb- Molar mass of Gram A
2- Coefficient of mole B
1- Coefficient of mole A
169.872g Ag(NO3)- Grams B
I multiplied across the top then divided by the bottom and came out with 19.8g of (Ag(NO3))
Limiting Reactant
In my case Ag(NO3) was my Limiting Reactant because there was the least amount of it in the reaction.
Excess Reactant
In my reaction Pb is my excess reactant because i have it left over.
Theoretical Yield
The Reaction that comes out the least is the theoretical, because there is less and it limits the reaction to that amount.
In my equation the theoretical yield is (7.18 Ag) compared to (12.806 Pb), Ag is the theoretical yield because it is the smallest.
Percent yield
Formula-
(Actual) / (Theoretical) x (100)= (Percent Yield)
My Reaction-
7.81g of Ag- Theoretical
9.02g of Ag- Actual
9.02 / 7.81 x 100= (115.4%)
115.4% is my Percent Yield