# Chapter 10

## Practice Problem

You enter in a drawing contest and you have to draw a circle with the given measurements. A=? r=5cm

A=πr^2

A= 3.14*25

A=78.5cm^2

## Vocab

Polyhedron: is a solid that is enclosed by polygons. Only flat surfaces.

Solid: a 3-dimensional figure that encloses a part of space

Faces: The polygons that form a polyhedron

Edges: the segments where faces of a polyhedron meet.

Vertex: A point where 3 or more edges meet.

## Surface Area of a Prism

S=2B + Ph

The Surface Area of a prism is the sum of twice the area of a base B and the product of the base's perimeter P and the height h

## Surface Area of a Cylinder

S=2B + Ch= 2πr^2 + 2πrh

The surface area of a cylinder is the sum of twice the area of a base B and the product of the base's circumference C and the height h

## Surface Area of a Triangular Prism

S=2B + Ph

S=2(1/2*b*h) + Ph

The surface area of a prism is the sum of twice the area of a base B and the product if the base's perimeter P and the height h.

## Vocab

Radius: the distance between the center and any point on the circle.

Circumference: the distance around the circle.

Diameter: the distance across the circle through the center.

Slant Height: the height of any face that is not the base of a regular pyramid

Surface Area of a Square Pyramid

## Chapter 6: Volumes of prisms and Cylinders

Cylinder Volume and Surface Area

## Formulas

Chapter 1

• Area of a Parallelogram: A=bh
• Area of a Trapezoid: A=1/2(b1 + b2)h
Chapter 2
• Area of a Circle: A=πr^2
Chapter 4
• Surface Area of a Prism: S=2B+Ph
• Surface Area of Cylinder: 2πr^2 + 2πrh
Chapter 5
• Surface Area of Pyramid: S= B+1/2PL
• Surface Area of a Cone: S= πr^2 + πrL
Chapter 6
• Volume of a Prism: V=Bh
• Volume of a Cylinder: V=πr^2h
Chapter 7
• Volumes of a Pyramids: V=1/3Bh
• Volumes of a Cone: V=1/3πr^2h
B= πr^2

• Area of a triangle: A= bh1/2