# Glucose and Oxygen

### Learn the ways of stoichchemistry!

## Reactions

**Glucose and Oxygen**

**Type of reaction: **Combustion (because oxygen is always present mainly if something is burning.)

**Usage in reality:** Oxygen is transferred from all life on Earth and is also a part of combustion as it reacts as a gas.

**Glucose:** Provides supplements for plants and is present in almost everything consumable. It benefits the cellular respiration period within plants and gives out to organisms.

## Balanced equations and state of matter

C*6 H*12 O*2 +6O*2==6CO*2= 6H*2 O+25ATP ( carbon hydrogen oxide yields dioxide)

Molar Mass of Oxygen: 32g

Molar Mass of Glucose: 180.16g

## Limited and excess reactants Limiting & excess reactant: Place out your givens then start with either one and convert by the molar mass to moles then the coefficient ratio. Finally, convert the molar mass of the other reactant and repeat these steps with the other one. Once you've found your limited and excess reactant, always circle the limited reaction as it tells you how much of a product can be used before it becomes impossible. | ## Theoretical and yield percent Theoretical & percent yield: To find the theoretical yield you must use your given and solve similar to a mass to mass or mole to mole problem. After you've found your theoretical, divide it by your given actual yield. Then multiply by 100. | ## Mass to mass Mass to mass: Start with your given then write out the molar mass of the given. Next write out your coefficient ratios then convert the mole of the other ration to grams. Multiply all top then divide all bottom totaled. |

## Limited and excess reactants

## Theoretical and yield percent

## Conversions and Reactants

**Mole to mole:**First, start off with your given then write out the coefficients for your ratio after you've balanced. Next multiply all from the top then divide the bottom. Make sure units are identical in order to cancel as you convert!

**Mass to mass: **Start with your given then write out the molar mass of the given. Next write out your coefficient ratios then convert the mole of the other ration to grams. Multiply all top then divide all bottom totaled.

**Limiting & excess reactant: **Place out your givens then start with either one and convert by the molar mass to moles then the coefficient ratio. Finally, convert the molar mass of the other reactant and repeat these steps with the other one. Once you've found your limited and excess reactant, always circle the limited reaction as it tells you how much of a product can be used before it becomes impossible.

**Theoretical & percent yield: **To find the theoretical yield you must use your given and solve similar to a mass to mass or mole to mole problem. After you've found your theoretical, divide it by your given actual yield. Then multiply by 100.