Calcium Carbonate + Nitric Acid

By: Vance Wade

Balanced equation

CaCO3(s) + 2HNO3(aq) --> Ca(NO3)2(aq) + H2O(l) + CO2(g)

Molar Masses:

CaCO3(100.0872) HNO3(63.01) Ca(NO3)2(102.08294) H2O(18.014) CO2(44.0098)

Calculations

Mole to Mole:


(11.30 mol CaCO3*1 mol ca(NO3)2)/ 1 mol CaCO3


= 11.30 mol Ca(NO3)2


(12.1 mol H2O*2 mol HNO3)/ 1 mol H2O


= 24.2 mol HNO3


Mass to Mass:


(1.17 g CaCO3*1 mol CaCO3*1 mol Ca(NO3)2*102.08294g Ca(NO3)2)/(100.0872 g CaCO3*1 mol CaCO3 *1molCa(NO3)2)


=1.19 g Ca(NO3)2



Limiting and Excess reactants:

(5.25 g CaCO3*1 mol CaCO3*1 mol CO2*44.0098 g CO2)/(100.0872 g CaCO3*1mol CaCO3*1 mol CO2)


= 2.30 g CO2 CaCO3= Limiting reactant


(12.18 g HNO3*1 mol HNO3*1 mol CO2*44.0098 g CO2)/(63.01 g HNO3*2 mol HNO3*1 mol CO2)


=4.25 g CO2 HNO3= Excess reactant

Theoretical Yeild:

2.30 g CO2