Calcium Carbonate + Nitric Acid
By: Vance Wade
Balanced equation
CaCO3(s) + 2HNO3(aq) --> Ca(NO3)2(aq) + H2O(l) + CO2(g)
Molar Masses:
CaCO3(100.0872) HNO3(63.01) Ca(NO3)2(102.08294) H2O(18.014) CO2(44.0098)
Calculations
Mole to Mole:
(11.30 mol CaCO3*1 mol ca(NO3)2)/ 1 mol CaCO3
= 11.30 mol Ca(NO3)2
(12.1 mol H2O*2 mol HNO3)/ 1 mol H2O
= 24.2 mol HNO3
Mass to Mass:
(1.17 g CaCO3*1 mol CaCO3*1 mol Ca(NO3)2*102.08294g Ca(NO3)2)/(100.0872 g CaCO3*1 mol CaCO3 *1molCa(NO3)2)
Limiting and Excess reactants:
(5.25 g CaCO3*1 mol CaCO3*1 mol CO2*44.0098 g CO2)/(100.0872 g CaCO3*1mol CaCO3*1 mol CO2)
= 2.30 g CO2 CaCO3= Limiting reactant
(12.18 g HNO3*1 mol HNO3*1 mol CO2*44.0098 g CO2)/(63.01 g HNO3*2 mol HNO3*1 mol CO2)
=4.25 g CO2 HNO3= Excess reactant
Theoretical Yeild:
2.30 g CO2