Lead(II) Nitrate & Potassium iodide

By: Dustin Repp 1st

Type of Reaction:

Double Replacement

Balanced Equation

1 Pb (NO3)2 + 2 KI = 2 K (NO3)+ 1 PbI2

IUPAC name

Lead Nitrate plus Potassium Iodide reacts to make potassium Nitrate plus Lead Iodide

Molar Mass

Pb(NO3)2= 331.208

KI= 166.002

K(NO3)=101.102

PbI2= 461.009

Mole To Mole= 12.14 MolPbI2

[3.10g pb (NO3)2][ 1 MolePbI2]

--------------------------[1 Mole Pb(NO3)2]

Mass To Mass= 16.84g PbI2

[12.1g Pb(NO3)2][1Mole]------------------[1PbI2]------------------[461.oo8g PbI2]

------------------------[331.208g Pb(NO3)2][1 Mole Pb(NO3)2][1 Mole]

Limiting and Excess Reactant= 7.5g K(NO3) and 7.4g K(NO3)

[12.3gPb(NO3)2][1 Mole]-----------------[2 Mole K(NO3)]---[101.102g K(NO3)

------------------------[331.208gPB(NO3)2][1 Mole Pb(NO3)2][1 Mole K(NO3)]


[12.3gKI2][1Mole KI][2 Mole K(NO3)][101.102g K(NO3)]

---------------[166.002][2 Moles KI]-------[1 Mole]

Theoretical Yield= 7.4g K(NO3)

Percent Yield= 91.9%

6.8gK(NO3)/7.4gX100