Lead(II) Nitrate & Potassium iodide
By: Dustin Repp 1st
Type of Reaction:
Double Replacement
Balanced Equation
1 Pb (NO3)2 + 2 KI = 2 K (NO3)+ 1 PbI2
IUPAC name
Lead Nitrate plus Potassium Iodide reacts to make potassium Nitrate plus Lead Iodide
Molar Mass
Pb(NO3)2= 331.208
KI= 166.002
K(NO3)=101.102
PbI2= 461.009
Mole To Mole= 12.14 MolPbI2
[3.10g pb (NO3)2][ 1 MolePbI2]
--------------------------[1 Mole Pb(NO3)2]
Mass To Mass= 16.84g PbI2
[12.1g Pb(NO3)2][1Mole]------------------[1PbI2]------------------[461.oo8g PbI2]
------------------------[331.208g Pb(NO3)2][1 Mole Pb(NO3)2][1 Mole]
Limiting and Excess Reactant= 7.5g K(NO3) and 7.4g K(NO3)
[12.3gPb(NO3)2][1 Mole]-----------------[2 Mole K(NO3)]---[101.102g K(NO3)
------------------------[331.208gPB(NO3)2][1 Mole Pb(NO3)2][1 Mole K(NO3)]
[12.3gKI2][1Mole KI][2 Mole K(NO3)][101.102g K(NO3)]
---------------[166.002][2 Moles KI]-------[1 Mole]
Theoretical Yield= 7.4g K(NO3)
Percent Yield= 91.9%
6.8gK(NO3)/7.4gX100