# Balloon Project

### I ðŸ’š math!

## Problem 2

## Problem 3 The balloon was at an altitude of 900 feet 5 minutes before it was sighted. This is because it was sighted at an altitude of 800 feet, and it is descending at a rate of 20 feet per minute. | ## Problem 4 It takes the balloon 40 minutes to land, because 40 times 20 is equal to 800. This is is shown in the graph. For the same reasons, it takes the balloon 39 minutes to reach an altitude of 20 feet. | ## Problem 5 As shown in the graph, it takes the second balloon 20 minutes longer to land. The red line shows the first balloon, and the green line shows the second balloon. There is a 20 minute difference between their landings, which is shown in the x axis. |

## Problem 3

The balloon was at an altitude of 900 feet 5 minutes before it was sighted. This is because it was sighted at an altitude of 800 feet, and it is descending at a rate of 20 feet per minute.

## Problem 4

It takes the balloon 40 minutes to land, because 40 times 20 is equal to 800. This is is shown in the graph. For the same reasons, it takes the balloon 39 minutes to reach an altitude of 20 feet.

## Question 7

f(x)=30x

They will be the same altitude at 480 feet, and at 16 minutes.

Graphically, it means the two lines are intersecting.

## Problem 8

1200 feet. This is because the balloon is descending at a faster rate, so it would have to start at a higher altitude in order to land at the same time as the first balloon. The proportion is 20/800=30/x.

The function of the line is f(x)= 1200-30x.