The Guide to Stoich
Mujtaba Baig
What is Stoichiometry
Stoichiometry is the relationship the relative quantities of substances taking part in a reaction or forming a compound, typically a ratio of whole integers. Stoichiometry is used in many aspects of the real world, such as cooking, which is a major use in Stoichiometry. The type of reaction i received was Single Replacement. You can identify Na+H20 is Single Replacement because the Na replaces the H and the Sodium is higher according to the activity series.
Cooking
Stoichiometry is used in cooking because elements are reacting constantly in cooking which requires conversions.
Balanced Equation for Na+H2O
The Balanced Equation for Na+H2O=NaOh=H2 is 2Na+2H2O=2NaOH+H2. 2NaOH is aquis(aq) and H2 is in gas form.
IUPAC Name and Molar Mass
The IUPAC Name for Na is Sodium. For H2O the IUPAC name is water. The IUPAC name for H2 is Hydrogen and the IUPAC name for NaOH is Sodium Hydroxide. The Molar Mass of 2Na is 24.9898 g/mol. The Molar mass of 2H2O is 20.0148 g/mol. The Molar mass of 2NaOH 41.9967 g/mol. Finally, the molar mass for H2 is 2.0158 g/mol.
Mole to mole Conversions, Mass to Mass Conversions, and limiting & excess reactant.
The guide
For the mole to mole conversions, You have to do mole to mole for NaOH. First you set up the train track method and put 11.3 mol of Na, and the next line put 2NaOH which underneath you put 2 Na, and they cancel out which the result is 11.3 mol NaOH. The second one is for H2O , so you make the train track method, then write 12.1 mol of H2O and on the right H2 and underneath 2H20 which cancel and divide 12.1 by 2 to get 6.05 mol of H2O.
For the mass to mass conversions to find the mass of H2O which the only one we need to find you set up the train track method and write 32.253 g/mol and to the right you put 1 mol and underneath 6.05 mol of H2O. Divide 32.253 by 6.05 to get 5.33 g which is the mass to mass conversion.
For limiting and excess reactant first you would set up the train track method. First you would put 5.2 g of Na which is the amount given. Diagonal put 22.290 g/mol and on top 1mol of Na because it will always be 1 mol. To the right put 2 mol B and underneath 2 mol. Then to the right put 36.03 g/mol and underneath 1 mol of H2O, Calculate by multiplying on the top and divide by the bottom to get 33.6 g 2H2O which is the answer.
The Theoretical Yield and Percent Yield
The theoretical yield is 32.6 for H20. And the percent yield is calculated by measuring dividing the actual yield by the theoretical yield and multiply by 100. So you do 11.3/32.6 *100 which is 34.66% yield.