Hot Air Balloon
Jessica, Jack, and Hiro
Question #1
f(x)=800-20x
Question #2
Graph can be found below.
Question #3
900 ft in the air, 100 ft higher than the 1st balloon.
Because it decends at a rate of 100 ft every 5 minutes, it would be at 900 ft 5 minutes before it was at 800 ft.
Question #4
It takes 40 minutes to land, and 39 minutes to be 20 ft in the air.
Because it decends at a rate of 20ft every minute (100ft every 5 minutes). 800 divide by 100 times 5 =40. since it desends 20 ft evey minuet, 40 minus 1 = 39, 20ft above ground.
Question #5
A second balloon is first sighted at an altitude of 1200 feet but is descending at 20 feet per minute. Write the function that represents this situation. How much longer does it take for the second balloon to land compared with that of the first balloon? How does the descent of the balloons compare. Show the graph. Explain the relationship between the two lines.
f(x)=1200-20x. It takes ! hour which 20 minutes longer than first ballon.
since it decends at same rate, it's parallel- never touching each other.
Question #6
A third balloon is first sighted at an altitude of 800 feet but is descending at 30 feet per minute. Write the function that represents this situation. How much longer does it take for the third balloon to land compared to the first balloon? How does the descent of the balloons compare? Show the graph. Explain the relationship between the two lines.
f(x)=800-30x. 26 1/3 minuets to land and 13 2/3 minutes longer .
It intersects at y-axis because it's not same rate. third ballon desends faster, rate of -30ft every minutes.
Question #7
f(x)=30x
They'll be at the same altitude at 16 minutes, 480 feet.
Question #8
An altitude of 1210 feet.
y=1210-30x