Lead (II) Nitrate and Sodium Bromide
What about my reaction?
What more can we learn about this reaction?
Lead (II) Nitrate
An aqueous ionic compound between a lead isotope and nitrate.
An aqueous covalent compound that is made up of sodium and bromine.
Sodium Nitrate and Lead (II) Bromide
The reaction between the two compounds results in 2 new compounds that create a precipitate.
The Equations and Formulas
Mole to Mole conversion
Mass to Mass
For this equation I was given a mass of 11.25 grams for Pb(NO3) and had to find how much mass of NaNO3 was present
If you don't quite understand the way I described mole to mole or mass to mass conversions here is a video to help out
Limiting and Excess Reactants
For example in my reaction if my limiting reactant was PbNO3 and it had 5.25g that would give a yield of 2.59 g of PbBr2. My excess reactant would therefore be NaBr let's say there's 12.18 g of it. that would allow for the creation of 7.8g of PbBr, but since the Lead (II) Nitrate limited the reaction there is let over Sodium Bromide.
If you need an easier way to understand Limiting and Excess reactants
Theoretical and Percentage Yield
When I was given the variable of 3.62g of actual yield I divided by the theoretical yield to get a PY of 139.7%. This is technically impossible. You can't have more solution than you start with, but it is because the reaction was rushed and there wasn't enough time for all the impurities to come out, or the reaction isn't yet dry.
If you don't understand Theoretical and Percentage Yield here is a video to help