# The Journey to Learn Quadratics

### By:Sara Khaliqi

Hello ladies and gentlemen! Welcome to Sara Khaliqi's website designed to teach everyone about grade 10 quadratics. Not only is this useful for all of you, but Sara Khaliqi just might use this INCREDIBLE website in the years to come to review quadratics. Now, sit back, relax and get ready to read, watch, and learn about quadratic relationships, expressions, and equations.

## Did you know?

The origin of the word quadratics is Latin. Quadratics is derived from quadratus which is the past participle of quadrare which means "to make square." This refers to the fact that the highest exponent is a square (i.e., x^2+2x+1 where ^2 is the highest exponent).

Introduction

- Characteristics of a Parabola

- Second Differences & Quadratic Relations

- Transformations

Also, in this course, we learned that Quadratic equations and relations can come in 3 different forms:

- Vertex form

- Factored form

- Standard form

Vertex form

- Determining an equation when given the vertex

- Isolating for x

- Graphing vertex form

Factored form

- Roots

- Expanding

- Graphing factored form

Standard form

- Common factoring

- Binomial common factoring

- Factoring by grouping

- Perfect squares

- Difference of squares

- Factoring simple trinomials

- Factoring complex trinomials

- Completing the square

- Discriminant

- Graphing standard form

Word Problems

- Optimization

- Motion Problems

- Revenue Problems

- Shape Problems

- Area Problems

Structure of a Parabola

There is much more to a Parabola other than just a line, like linear relations. A parabola is the shape a quadratic relation takes when it is graphed.

The Vertex is the maximum of minimum point on the graph. For parabola's facing upward, the vertex is the minimum point and for parabola's facing downward, the vertex is the maximum point.The vertex is the location where the parabola starts to change its direction.

The Optimal Value is also known as the maximum/minimum value. For parabola's facing upward, the optimal value is the minimum value and for parabola's facing downward, the optimal value is the maximum value. The y-coordinate of the vertex is always the same as the optimal value. To find out the optimal value, look at the y-value of the vertex.

The Axis of Symmetry of a parabola is a vertical line that cuts the parabola into two equal halves. The x-coordinate of the vertex is always the same as the axis of symmetry. the axis of symmetry is located halfway between the zeroes, if there are any.

Direction of Opening: The direction of opening of a parabola is the way the parabola is facing. A parabola can open in 2 directions; upwards or downwards. In any form( standard, factored, vertex), a parabola facing downwards would have a negative a value. A parabola facing upwards would have a positive a value.

Zeroes are also known as the x-intercepts or roots. A parabola does not always have x-intercepts, but the maximum amount of x-intercepts in a quadratic relation is 2. The x-intercept is the point where the parabola intersects with the x-axis.
The y-intercept is the area where the parabola intersects with the y-axis. No matter what. a parabola must have one y-intercept and no more than just one.The y-intercept can be found by subbing in x=0 in a quadratic equation.
Finally, there are possible x-values and possible y-values for parabolas.

Possible x-values for any parabola will always be a set of real numbers.This is due to the fact that all x-values are possible on any parabola ( if you extend the arms all the way, then all the real numbers on the x-axis are possible x-values).

Possible y values depends on the optimal value.These are the possibilities based on the optimal value and if the optimal value is a maximum or minimum. So if the optimal value is a maximum (opening downwards), then the possible y-values are all real numbers less than the optimal value (possible y-value <optimal value). If the optimal value is a minimum( opening upwards), then the possible y-values are all real numbers greater than the optimal value (possible y-values > optimal value).

Example: Lets find the direction of opening,vertex, axis of symmetry, optimal value, possible x-values and possible y-values for the parabola with the equation:Y=-(x-4)^2+12

I know that the a-value is -1 the -1 in this example is in the same place as the a value in because in the basic vertex form equation (look at section: types of equations) Y=a(x-h)^2+k h.

Just by looking at the a value, I know that the parabola will be facing downwards. I know this because The a value( leading coefficient) is -1 and when the a value is negative, then the parabola faces downward.

The axis of symmetry is x=4 and I know because this equation is in vertex form so I need to know what number will add into the bracket (x-4) to isolate x and the number is 4.

The optimal value is 12 and I know because in vertex form (y=a(x-h)^2+k) the k value is the optimal value so that is why the optimal value is y=12

Now that I know the axis of symmetry and the optimal value, I know the vertex since the axis of symmetry is the x value of the vertex and the optimal value is the y value of the vertex so the vertex is (4,12).

I also know that the vertex is the maximum ( because the parabola is facing downward).

Possible x-values are a set of all real numbers. Possible y-values are all real numbers less than 12. ( since the optimal value is 12, with the parabola opening downward).

In grade nine, I learned that if first differences are constant, then the graph represented a linear relation. But if the first differences are not constant, then the graph is not linear.

Now, I know that if the second differences are constant, then the graph represents a quadratic relation. To calculate the second differences, we must first calculate the first differences.

When you have table of values of x and y, you can determine whether or not the relationship is quadratic by using first and second differences.

Step 1: To find the first difference, subtract one y-coordinate from the one above it.** Remember to skip the first row since there is nothing above the first row. Continue this until the column is filled. If the first differences are the same, then the relation is linear.

Step 2: To find the second differences, subtract one first difference from the one above it.** Remember to skip the first 2 rows. Then, if the second differences are the same, that means that the relation is quadratic. If the second differences are not constant, then the graph represents a relation that is not quadratic or linear.

Lets do an example!

Transformations

Parabolas go through transformations to become the 'final parabola' as a result. The three transformations parabolas go through are Stretching or Compressing, Reflecting, and Translating. The order that the transformations come in is Stretch first, then Reflect then Translate, and SRT is an easy way to remember this.

Stretch - The stretch is the first transformation parabolas go through before any of the others. The stretch refers to the a value in the standard, factored or vertex form equation. For a parabola to be stretched, the a value must be greater than 1. For example, the parabola y=3x^2 (a value is 3) is stretched vertically. For a parabola to be compressed, the a value must be less than 1, but greater than 0. For example, the parabola y=0.5x^2 (a value is 0.5) is compressed vertically.This includes decimals and fractions. In both cases, stretch and compression, the step pattern is altered. The basic step pattern is over 1, up 1 and over 2, up 4. With the stretch/ compression factor, the vertical (up/down)part of the step pattern is changed. The stretch factor is multiplied by the vertical part, and the outcome is the new step pattern.The step pattern helps lead to points that lie on the parabola.

For example a quadratic equation is y=3(x-4)^2+4. since the a value is three, the step pattern changes so I will multiply the a value to the vertical part of the step pattern (up/down).

Over 1, up 1x3= 3

Over 2, up 4x3= 12

Therefore, in this case, the step pattern is over 1, up 3 and over 2, up 12.

Reflect - In grade 10, the only reflection learned was a reflection occurring in the x-axis. When a parabola is reflected, the direction of opening is flipped. For example, a parabola can start off with facing upward, but if the parabola is reflected in the x-axis, the result is the parabola facing downward. A hint to know if a reflection occurs to see if the a values sign (-/+) is opposite in the starting equation and the final equation for the parabola.

For example, the equation y=x^2 transforms to the equation y=-x^2. With this, the starting equations a value was positive and the final equations a value is negative. Therefore, a reflection in the x-axis occurred.

Translate - This is the last transformation that is applied to the parabola. A parabola can translate horizontally and vertically. A vertical translation moves the parabola left and right and the horizontal translation moves the parabola up and down. In the equation y=a(x-h)squared+k, h is the variable that represents the horizontal translation and k is the variable that represents the vertical translation. If k is positive, then the parabola is translated up, but if k is negative, then the parabola is translated down. If h is negative, then the parabola moves to the right, and if h is positive, the parabola moves to the left. This is because when you try and isolate x in the bracket, h must be removed and to do so, you must add h if h is negative, and subtract h if h is positive.

For example, the quadratic equation transforms to the quadratic equation y=(x-4)^2+4, the bracket is (x-4)

Now, to isolate the x, I will have to get rid of -4 by adding 4.

x-4+4=0+4

x=4

since +4 is the number I add to the equation, that means that the parabola is going to translate 4 units to the right.

And the k value is +4, so the parabola is translated 4 units up

Therefore, this parabola is translated 4 units to the right and translated 4 units up.

Example: ~Describe how a parabola has gone from y=x^2 to a different vertex form equation.For example, the equation y=-4(x+6)-3

1) the a value is 4 which means the graph stretches by a factor of 4.

2) the a value is negative so it reflects in the x-axis

3)the h value is -6, so the graph shifts 6 units to the right

4)the k value is -3, so the graph shifts down 3 units

Every type of quadratic expression/equation has a y-intercept because if the arms of the parabola are extended, the parabola will eventually hit the y- axis. To find out the y-intercept in each form, you must set x=0 and then continue to solve.

This section shows you how to find the vertex and x-intercepts of parabolas in each form.

1. Vertex form: The basic quadratic equation in vertex form is; y= a(x-h)²+k

Remember that the Axis of Symmetry in vertex form can be found by simply looking at the equation. The axis of symmetry is the x value in the vertex so if the equation is y=(x-2)²+3, then we need to find the vertex. I know that to get rid of the -2 in the bracket, I need to add 2. This 2 is the x-value of the vertex and the y value=3.Since the vertex is (2,3) then the axis of symmetry would be 2. Th optimal value of an equation in vertex form can also be found by looking at the value of k. In the equation y=(x-2)²+3, the k value is 3 and therefore, the optimal value is y=3. Recall that the optimal value is also the y-value in the vertex.

To find the x-intercepts in vertex form, the method called isolating for x must be used. Look at the "isolating for x" part in the vertex form section to understand the method more and to see an example.

3. Factored form: The basic quadratic equation in factored form is; y=a(x-r)(x-s)

In this form, the a value represents the stretch value. If 'a' is negative, then that indicates that the graph is facing downward. If 'a' is positive, then the graph will be facing upward.

To find the x-intercepts, look at both brackets.

Example: y= (x-4)(x-2) Each bracket represents an x-intercept so if one bracket is (x-4), then you must figure out which number should be added to isolate x and in this case, 4 is the number that will do so. So, one x intercept is (4,0).

(x-4)

(x-4+4)=0+4

x=4

The other bracket is (x-2):

(x-2)

x-2+2=0+2

x=2

To find the vertex of a parabola using factored form, you must first find out the axis of symmetry and the optimal value. To find the axis of symmetry, you must add both r and s together, then divide the sum by two. So, axis of symmetry: x= r+s/2

Once you have obtained the axis of symmetry, you must find the optimal value by substituting the axis of symmetry into the equation.

For example, if my axis of symmetry was 3 and my equation was y= (x-4)(x-2), then I would substitute 3=x into the equation and solve for y:

Y= (x-4)(x-2)

Y= (3-4)(3-2)

Y=(-1)(1)

Y=-1

Therefore, in this case, the vertex is (3,-1) and the x-intercepts are (4,0) and (2,0).

## Vertex Form

Finding an equation when given the vertex

Sometimes, a question will give you the vertex with another point on the parabola and will ask you to figure out the equation. Here is an example:

Example #1: The vertex of a parabola is (-4,3). The parabola goes through the point (-5.1).

Isolating for x:
Graphing vertex form: Here are 2 examples of graphing vertex form.

In the first example, the a value is 1, which means that it can follow the basic step pattern.

In the second example, there is a negative a value in the equation and the a value is -2, which means it cannot follow the basic step pattern.

In conclusion, vertex form gives 3 different pieces of information:

A value represents the stretch value. If the a value is negative, the parabola will open downward and if the a value is positive, the parabola will open upward.

K represents the vertical translation and h represents the horizontal translation

Following the translations of h and k will lead one to the vertex of the parabola. Once the vertex is plotted, the step pattern can be followed. Therefore, vertex form gives the vertex, axis of symmetry, and optimal value of the parabola.

## Factored Form

Roots:

A zero of a parabola is another name for the x- intercepts and in order to find the x- intercepts you must set y=0. Please look at the types of equations to understand how to find the x-intercepts of a quadratic relationship in factored form.

Key points

When the (a) value changes the zeroes do not change.

When the (a) value changes the axis of symmetry does not change

When the (a) value changes the optimal value changes as well.

Expanding: is used to convert factored form into standard form
Graphing factored form:

## Standard Form

When we go from standard form to vertex form, we use a method called factoring. There are 7 types of factoring listed below.
Common factoring:
Binomial Common Factoring
Factoring by Grouping:
Factoring Simple Trinomials
Factoring Complex Trinomials:
Perfect Squares:
Difference of Squares:
Completing the Square:
Discriminant:
Graphing Standard Form:

The first thing to graph with standard form is the y-intercept. In the equation, the c value is the y-intercept.

## Word Problems

Here are 9 videos on the different types of word problems that use quadratic knowledge and the different ways of approaching each question.
Optimization: Optimization is what some problems ask us(ex, Revenue problems asking to Find the maximum revenue and the number of increases in the price to achieve the maximum revenue). This means that the problem is asking for the maximum/minimum. In the beginning, we learned that the vertex is the maximum/minimum point on a parabola. So when we are asked to find the max/min of something (ex., revenue of a purse), we have to find the vertex. Watch the revenue problem video and the area problem video for an example.
Motion Problems:

(Side note: There are two videos for example one so watch both parts to understand the full solutions)

## Example 1

Motion Problem Part 1
Motion Problem Part 2
Revenue Problems:

(Side note: There are two videos for example one so watch both parts to understand the full solutions)

## Example 1:

Revenue Problem Part 1
Revenue Problem Part 2
Shape/ Area Problems:

## Example 1

Shape/Area Problem Example 1

## Example 2

Shape/Area Problem Example 2
Number Problems:

## Example 1

Number Problem Example 2

## Example 2

Number Problem Example 3

## Example 3

Only watch this third video if you continue to have trouble. The third video is lengthy because I did one extra part to this problem.
Number Problem Example 1

## Connections

Throughout this website, I made connections between different quadratic topics. In this section, I will provide more connections that show that the different topics in quadratics are related. Remember, throughout this website, I have been making hints about connections so here are a few.

Graphing and Factoring relate because when we are trying to graph an equation in standard form, we must factor or use the quadratic formula to find the x-intercepts that we need to plot on the graph. Factoring is a method used to go from standard form to factored form and once we have factored form, we can set each factor to 0 so that we can find the x-intercepts. We can also just sub in the values of a, b, and c into the quadratic formula to get the x-intercepts of an equation in standard form. Without factoring (or using quadratic formula) a standard form equation, we wouldn't be able to plot the zeroes on our graph.

Factoring and the Quadratic Formula both relate to one another because both are used to find the x-intercepts of an equation. Factoring is used to go from standard form to factored form. When we have factored form, we can find the x-intercepts of a parabola by setting each factor to 0. With the quadratic formula, we are using an equation from standard form and substituting the values of a, b, and c to find the x-intercepts. Both methods get me the x-intercepts of an equation. In one of my videos, I use both methods to find the x-intercepts so go watch the videos to see and example.

Discriminant and X-intercepts:

The discriminant tells us how much solutions an equation (in standard form) will have. We learned that when D=0, there is only one solution. If D>0, then there is 2 solutions. If D<0, then there are no solutions. Solutions is another word for x-intercepts. When a parabola meets with the x-axis, the point of the coordinate at which they meet is the x-intercept. With this, we can easily know how much zeroes a parabola has before doing any other calculations. For example, if D=0, then I would right away know that there is only one x-intercept.

Forms of Equations and Stretch/Compression:

There are three forms of quadratic equations:Factored form,vertex form and standard form. All of them have the a value in common. When we want to go from standard form to vertex form, we use completing the square. Once we are done completing the square, we have 2 equations that represent the same parabola. And in these 2 equations, the a value (leading coefficient) will be the same no matter what.

For example, in the completing the square section, I had the equation Y=3x^2+36x-3 (standard form). When I completed the square, I got Y=3(x+3)^2-30 (vertex form).And this equation in factored form is y=3(x-0.08)(x+12.08).The similarity between these three is the a value. The a value never changed and was constant in all three equations. This means that no matter what form the equation is in, we will know if the parabola is being stretched or compressed based on the a value.

Completing the Square and Perfect Square Factoring:

Completing the Square and Perfect Square Factoring relate because when we are completing the square, we use perfect square factoring. When we want to go from standard form to vertex form, we use completing the square. One step in completing the square is to add and subtract a certain number into the bracket (review completing the square section). When we add and subtract that number, we then take out the subtracted number out of the bracket by multiplying it with the a-value. Then, we are left with a bracket containing a perfect square trinomial. We use our knowledge on perfect square factoring in completing the square

Characteristics of A Parabola and Completing the Square:

These two topics relate to each other because when we use completing the square to go from standard form to factored form, we are finding out more about the characteristics of the parabola. For example, before completing the square, my equation was Y=x^2+4x+5. With this equation, I only knew the y-intercept was (0, 5) because of the c value. With just a first glance, that is all I know. After completing the square, my equation was Y=(x+2)^2+1(look at completing the square section to see how to complete the square). When I see this equation, I can tell right off the bat that the vertex is (-2, 1). The axis of symmetry is x=-2. The optimal value is y=1 and the optimal value is the minimum. The parabola faces upward (a value is +). Possible x-values are all real numbers. Possible y-values are a set of real numbers greater than 1. I found out all of this by looking at the equation.

Graphing and Forms of Equations:

Graphing and Equations relate because standard form, factored form, and vertex form are all able to be graphed.From each type of equation we need to find the x- intercepts then find the y and x value of the vertex. We use different methods for all three forms, but no matter what, we can graph all three forms. With vertex form, we know the vertex by looking at the equation, and we find out the x-intercepts by isolating for x. In factored form, we find out the zeroes by setting each factor equal to 0 and we can find the x value of the vertex (axis of symmetry) by adding the zeroes together and dividing by 2. We find the y value of the vertex ( opt. value) by subbing in the axis of symmetry from the step before. In standard form, we can factor/use quadratic formula to get the x-intercepts.We can find the x-value of the vertex by adding the zeroes together (the x-int's) and dividing by 2. Then, to find the y- value of the vertex, we sub in the axis of symmetry from the step before. These enable you to plot three points so you can graph.

## Reflection

Out of the three mini-units my favourite was quadratics 1 because it is easy to understand. Quadratics 1 consisted of graphing vertex form, transformations (stretch, reflect, translate) and the basic components of a parabola. I was able to understand what the vertex was, how to describe transformations, how to describe a parabolas characteristics ( direction of opening, optimal value, axis of symmetry, etc) and how to graph the parabolas with ease.For me, the information given on a graph was clear enough to answer some of the questions on the characteristics of the parabola.

I had the most trouble grasping the idea of Factoring. It was difficult for me to distinguish which type of factoring to use when I had to solve an equation.One thing I disliked about factoring was factoring complex trinomials. I did not like this part because we used the guess and check method, which was time consuming, and difficult to perform. It was not an accurate way, and took a lot of time because we had to guess the answer, instead of using a method that gave me the answer right away. Also, I always had a hard time identifying which factoring method to use. For example, in the test below, I got half a mark off of 7) because I didn't factor the difference of squares due to the fact that I did not notice that I could further factor after common factoring. This is why I did poorly on the "Mini Test 2:Quadratics"

Something that really helped me was using algebraic tiles to solve some of the factoring questions. They helped me actually understand the concept by being able to see how a standard form equation went into factored form. Also, after this mini test, I constantly practiced factoring and checking my answer to see if I factored successfully and fully. We had a second chance to do another Mini Test on Quadratics 2 and after all my practicing, I got a perfect score on the second "Quadratics 2 Test".
In the Quadratics 2 test, I checked all my answers and constantly made sure that I factored each question fully. The word problem on the last page was really cool because the problem was a real life application to baseball.
When we moved onto the quadratic formula in Quadratics 3, I very much enjoyed learning the formula,, and using it to find the x-intercepts, if given the standard form. I liked this a lot because the quadratic formula gave a more accurate answer and it easier to just substitute the values of a, b, and c into the formula rather than factoring to find the zeroes of a parabola.
Overall, quadratics was a new concept to me and some parts of quadratics was easier than others. But, I worked hard throughout the unit and I am happy that my skills have gotten better in many aspects of quadratics, including factoring. This website is a great way for me to review quadratics in years to come, and I learned a lot from creating this website