Stoich Project
Barium hydroxide and aluminum nitrate
Steps
Balanced Equation: 3Ba(OH)2+2Al(NO3) Yield 3Ba(NO3)2+2Al(OH)3
IUPAC name: Barium Nitrate, Aluminum Hydroxide
Molar Mass: Ba= 137.33 O= 16 H=1.01 + Al= 26.98 N=14.01 O=16 Yield Ba=137.33 N=14.01 O=16 + Al=26.98 O=16 H=1.01
Mole to Mole conversion: 171.35 * 213.01 divided by 171.35 = 213.01 Moles
Mass to Mass conversion: 12.1 * 1 * 2 * 213.01 divided by 171.35 * 3 * 1 = 90.25 Mass
Steps
The limiting reaction is A because it has less
Our Theoretical Yield is 90.25
the percent yield is 6.5*90.25*100 = 9025%