Stoich Project

Barium hydroxide and aluminum nitrate

Steps

Balanced Equation: 3Ba(OH)2+2Al(NO3) Yield 3Ba(NO3)2+2Al(OH)3

IUPAC name: Barium Nitrate, Aluminum Hydroxide

Molar Mass: Ba= 137.33 O= 16 H=1.01 + Al= 26.98 N=14.01 O=16 Yield Ba=137.33 N=14.01 O=16 + Al=26.98 O=16 H=1.01

Mole to Mole conversion: 171.35 * 213.01 divided by 171.35 = 213.01 Moles

Mass to Mass conversion: 12.1 * 1 * 2 * 213.01 divided by 171.35 * 3 * 1 = 90.25 Mass

Steps

The limiting reaction is A because it has less

Our Theoretical Yield is 90.25

the percent yield is 6.5*90.25*100 = 9025%

By: Destiny Burton