By: Temesgen Solomon
Type of Reaction
Since this is a double replacement reaction you replace two elements that are of the same matter for example in this problem you would replace Calcium and Hydrogen because they are both metals.
Name for each reactant and product
Ca(CO)3(aq) + 2HNO3(aq) → (CO2)(g) + Ca(NO3)2(aq) + H2O(l)
In this example Calcium Carbonate and Nitric acid are the reactants ,and Nitric Acid is the product.
An example of this is my first reactant Ca(CO3) in order to find the molar mass i would find the molar mass of calcium which is its atomic number. Second i would find the molar mass of Carbonate to do so i would find the atomic number of carbon which is 12.011 grams and add that by the molar of oxygen. However, one must multiply the molar mass of oxygen three times then add it to the molar mass of carbon and Calcium. That being said the molar mass of Calcium Carbonate would be 100.086 grams.
Mole to Mole conversions
11.30 Ca CO3 * 1 Ca CO3 mole/1 CO2 moles= 11.3 moles CO2
In this problem You start out with 11.30 moles of Calcium Carbonate and are trying to get to Carbon dioxide once you set it up like i have all one must do is multiply across, and divide across the bottom your answer will be answer will be 11.30 moles CO2.
Mass to Mass conversions
Step 1: After you right your given grams of an compound you put its molar mass on the bottom.
Step 2: Put one mole of that same compound over the molar mass of that compound.
Step 3: Then put the coefficient of the element that you started out with and put that under the coefficient that you are looking for.
Step 4: After step 3 is completed put 1 mole of whatever your looking for under the molar mass of whatever it is.
9.24 g Ca CO3 * 44.01 g CO2 /100.86 g Ca CO3=4.031 g CO2
Limiting and Excess reactant
For example if you have 5.25 g of Ca CO3 and 12.18 g of HNO3 and you wanted to know how much Carbon dioxide the two can hold you would go mass to mass on both to carbon dioxide then you determine which compound ends you with less grams of carbon dioxide. The answer is Ca CO3 which leaves you with 2.31 g of CO2.
Solve: 2.09 g/2.31 g * 100 = 90.5%